Question

factoring out;
-16t^2+64t-60=0

Answer 1

factor out -4 first, what u get ?

Answer 2

-4(4t^2-16t+15)=0

Answer 3

(?t -?)(?t -?) fill in the ?'s

Answer 4

(t-1)(t-15)=0

Answer 5

t=1 t=15

Answer 6

nopes, u need 2 numbers whose product is 15*4 = 60 and sum = -16
its easy, both numbers are negative

Answer 7

hmm.. I am confused now not sure.

Answer 8

-4(4t^2-16t+15)=0
-4(4t^2 - ? t-?t +15) = 0
what should replace those 2 ?'s
two numbers whose sum is -16 and product = 60

Answer 9

@malibugranprix2000 What numbers when multiplied together equal 60?

Answer 10

if u think a bit, its really easy

Answer 11

well there is 10 and 6

Answer 12

thats correct
-4(4t^2 - 10 t-6t +15) = 0
can u factor further ?

Answer 13

not sure how

Answer 14

ok,
-4(4t^2 - 10 t-6t +15) = 0
-4(2t(2t-5)-3(2t-5)) = 0
u see what i did there ?

Answer 15

oh I see

Answer 16

what u think should be next step ?

Answer 17

so is 2t-5=0, 2t-5=0 is taken out

Answer 18

-4(4t^2-16t+15) = -4(2t-3)(2t-5) = 0

Answer 19

yes, but we have other factor also, we write it like this
-4(2t(2t-5)-3(2t-5)) = 0
-4(2t-5)(2t-3)=0

Answer 20

2t-3=0 or 2t-5=0

Answer 21

it was asked to factor....
3 factors
-4,(2t-5),(2t-3)

Answer 22

{3/2,5/2}

Answer 23

I see now thanks a lot.

Answer 24

welcome ^_^

Answer 25

Don't forget to check the solutions in the original equation. @malibugranprix2000

Answer 26

thanks @hartnn and @skullpatrol