Question

How do i simplify this

Answer 1

\[\huge \frac{ 1+\frac{ sinx }{ cosx } }{ 1- \frac{ sinx }{ cosx } } =\]

Answer 2

\[\frac{ \sin x }{ \cos x } =\tan x\]

Answer 3

yea i am not allowed to use tan

Answer 4

i have to keep it only sin & cos that's why i simplified it originally from tan

Answer 5

\[ \frac{ 1+\frac{ \sin x }{ \cos x } }{ 1- \frac{ \sin x }{ \cos x } } =\frac{ \cos x+ \sin x }{\cos x- \sin x }\]

Answer 6

how did you do that ? :S

Answer 7

\[\frac{ 1+\frac{ \sin x }{ \cos x } }{ 1- \frac{ \sin x }{ \cos x } }\times1\]
\[\frac{ 1+\frac{ \sin x }{ \cos x } }{ 1- \frac{ \sin x }{ \cos x } }\times\frac {\cos x}{\cos x}\]
\[ =\frac{ \cos x+ \sin x }{\cos x- \sin x }\]\]