Question

∫∫1/(x^2+y^2)dxdy solve this converting in polar form
limits are
x :y to a
y :0 to a

Answer 1

Trying again?

\(\int\limits_0^a\int\limits_y^a \dfrac{1}{x^{2}+y^{2}}\;dxdy = \iint_A \dfrac{r}{r^{2}}\;drd\theta\)

You simplfy and tell me the new limits suggested by my "A".

Answer 2

new limits will be
r: 0 to a sec @
@:0 to pie/4

Answer 3

but now integral will be In r on applying limits I got problem

Answer 4

It's a little messy.