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Physics 19 Online
OpenStudy (anonymous):

How to determine tension in the string on both sides of the pulley?

OpenStudy (anonymous):

you'll need to give us the diagram though. the diagram is the clue.

OpenStudy (unklerhaukus):

|dw:1354526930481:dw|

OpenStudy (anonymous):

ok so i figured it out but maybe you can help me find a final velocity instead? haha

OpenStudy (anonymous):

lol alright

OpenStudy (anonymous):

okay so i have the equation 1/2m2vf^2 + 1/2m1vf^2 + 1/2Iwf^2 - m1gd + ukm2gd

OpenStudy (anonymous):

im trying to find vf (the final velocity) after moving a distance d = .700 m

OpenStudy (anonymous):

it's best if we got the original question though lol I'm guessing it will get easier if we apply the work-kinetic energy theorem

OpenStudy (anonymous):

1/2Iwf^2 being?

OpenStudy (anonymous):

final angular velocity

OpenStudy (anonymous):

and I is the inertia

OpenStudy (anonymous):

so the thing on top there equals?

OpenStudy (anonymous):

the total energy of the system

OpenStudy (anonymous):

no number?

OpenStudy (anonymous):

i dont think so

OpenStudy (anonymous):

oh! so you set the energy equations equal to each other! and then solve for vf?

OpenStudy (anonymous):

yup, I think. You've got two eqs equalling the same thing? then yeah. you should. lol

OpenStudy (anonymous):

okay let me try that! :)

OpenStudy (anonymous):

good luck :)

OpenStudy (anonymous):

thanks :)

OpenStudy (anonymous):

you're welcome :)

OpenStudy (anonymous):

okay it didnt work out with only vf ...crap this is awesome

OpenStudy (mayankdevnani):

Tension is the same on both sides of a mass less and frictionless pulley.

OpenStudy (anonymous):

yeah no im trying to find the final velocity after a distance d

OpenStudy (mayankdevnani):

these are examples

OpenStudy (anonymous):

no im not trying to find tension anymore but thanks :)

OpenStudy (mayankdevnani):

http://answers.yahoo.com/question/index?qid=20061210093447AAxc1rZ and welcome:)

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