How to determine tension in the string on both sides of the pulley?
you'll need to give us the diagram though. the diagram is the clue.
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ok so i figured it out but maybe you can help me find a final velocity instead? haha
lol alright
okay so i have the equation 1/2m2vf^2 + 1/2m1vf^2 + 1/2Iwf^2 - m1gd + ukm2gd
im trying to find vf (the final velocity) after moving a distance d = .700 m
it's best if we got the original question though lol I'm guessing it will get easier if we apply the work-kinetic energy theorem
1/2Iwf^2 being?
final angular velocity
and I is the inertia
so the thing on top there equals?
the total energy of the system
no number?
i dont think so
oh! so you set the energy equations equal to each other! and then solve for vf?
yup, I think. You've got two eqs equalling the same thing? then yeah. you should. lol
okay let me try that! :)
good luck :)
thanks :)
you're welcome :)
okay it didnt work out with only vf ...crap this is awesome
Tension is the same on both sides of a mass less and frictionless pulley.
yeah no im trying to find the final velocity after a distance d
1) http://answers.yahoo.com/question/index?qid=20090713184803AA9JygM 2) http://answers.yahoo.com/question/index?qid=20100430162455AAmJLJd
these are examples
no im not trying to find tension anymore but thanks :)
http://answers.yahoo.com/question/index?qid=20061210093447AAxc1rZ and welcome:)
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