Question

The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X.

What is the measure of angle ACB?

29°

8°

16°

21°

Answer 1

@jim_thompson5910

Answer 2

first you need to find the measure of arc AX

Answer 3

do you know how to do that

Answer 4

no

Answer 5

@jim_thompson5910 i have no clue how to solve this

Answer 6

use the inscribed angle theorem to get

AX = 2*(angle CBA)

AX = 2*42

AX = 84 degrees

Answer 7

ok...

Answer 8

now use the formula

angle ACB = (1/2)*(arc AB - arc AX)

angle ACB = (1/2)*(100 - 84)

angle ACB = ???

Answer 9

ACB = 8 ?

Answer 10

yep

Answer 11

ok thank you! :)