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For the first one, you can see that there are 5 terms. The first term is -3, and each subsequent term increases by 1. \[\sum_{k=0}^{4} ({-3 + 1i})\] See if you can do the next one
Sorry, I mixed i and k there. should be \[\sum_{k=0}^{4} (-3 + 1k)\]
alternatively, you can write it as: \[\sum_{k=1}^{5} (-4 + k)\]
4 n=1 (1+9)?
@slaaibak
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Nope. The next one is a quadratic series, which means each term is n^2 So, in this one there are 6 terms. It would be best to start counting at k=1: \[\sum_{k=1}^{6} k^2\]
Do you understand @coolaidd ?
yes.. thanks @slaaibak !
it's a pleasure.
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