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find any point (a,b) on the curve x^2+xy=2y-8 where the tangent line at the point is vertical?
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take the derivative and find where it is undefined
\[x^2+xy=2y-8\] \[2x+y+xy'=2y'\] solve for \(y'\)
\[2x+y=2y'-xy'\] \[2x+y=(2-x)y'\] \[\frac{2x+y}{2-x}=y'\] undefined if \(x=2\)
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