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OpenStudy (anonymous):
(secx-cosx)/tanx I get that it becomes ((1/cosx)-(cosx))/(sinx/cosx), but how does it become 1-cos^2x/cosx?
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OpenStudy (amistre64):
\[\frac1c-c=?\]
OpenStudy (amistre64):
looks to be a sin denominator in the end, nota cos ... but i cant see it that clearly yet
OpenStudy (amistre64):
\[(\frac1c-c)\frac cs=\frac{1-c^2}{s}=\frac{s^2}{s}=s\]
OpenStudy (anonymous):
in that case, where did the cosine denominator in the (1/c-c) go? I get that you would multiply by the reciprocal of tangent, or cotangent, but where did the cosine go?
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