Question

(secx-cosx)/tanx

I get that it becomes ((1/cosx)-(cosx))/(sinx/cosx), but how does it become 1-cos^2x/cosx?

Answer 1

\[\frac1c-c=?\]

Answer 2

looks to be a sin denominator in the end, nota cos ... but i cant see it that clearly yet

Answer 3

\[(\frac1c-c)\frac cs=\frac{1-c^2}{s}=\frac{s^2}{s}=s\]

Answer 4

in that case, where did the cosine denominator in the (1/c-c) go? I get that you would multiply by the reciprocal of tangent, or cotangent, but where did the cosine go?