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log2(5x)-log2(5)=100
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\[\log_{2} 5x-\log_{2}5=100\]
log2(x) = 100
Would I just do 5x-5=100?
x= 2^100
How? I don't understand.
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log 2(x) = 100 => x = 2^100
How do I get from log2(5x)-log2(5)=100 to log 2(x)?
5x/5 = x
@petewe, you didn't explain anything that would help @melbel understand
i'd assumed basic logarithm properties were known.
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