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Mathematics 19 Online
OpenStudy (anonymous):

How can you tell if a function is differentiable without graphing it?

OpenStudy (anonymous):

there are some classes of functions that are known to be differentiable. For example all polynomials are differentiable.

OpenStudy (anonymous):

yes, I remember that! c: Any other rules?

OpenStudy (anonymous):

So you can first see if it fits into a class of functions that are known to be differentiable.

OpenStudy (anonymous):

\[\frac{ x+1 }{ x }\]

OpenStudy (anonymous):

In particular, I was wondering how I could tell if this function is differentiable? And what about continuity?

OpenStudy (anonymous):

Well that function has a discontinuity at x=0. So if you wondered how much the function is changing at that point, it would be undefined. So it has no derivative at that point.

OpenStudy (anonymous):

The question asked me to discuss the continuity in the interval of [1/2, 2]

OpenStudy (anonymous):

That's a rational function (ratio of two polynomial functions). It's known that they are continuous everywhere except where the bottom of the ratio is equal to zero, which is at x=0. So on [1/2, 2] it's continuous everywhere.

OpenStudy (anonymous):

Okay so rational functions are all continuous except if the bottom of the ratio is zero. Noted.

OpenStudy (anonymous):

So how can I understand if a function is continuous without sketching it or graphing it exactly?

OpenStudy (anonymous):

You kind of just look at it and try to imagine any problem areas that might come up for certain values of x... That's what I do anyway.

OpenStudy (anonymous):

For rational functions, you know you can't divide by zero, so you're going to have a problem when it's zero. Usually most functions (at least in earlier maths) will just be combinations of a few of the standard functions, where you get some intuitive idea about what could go wrong.

OpenStudy (anonymous):

Okay, well I've got a good understanding of it now to complete my homework.

OpenStudy (anonymous):

Thank you for your help! I appreciate it! c:

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