Question

cos^2[(pi/2)-x]
divided by cosx

how does this match with sinxtanx

Answer 1

\[\cos ^2[(\Pi/2)-x]/cosx\]

Answer 2

hint : cos(pi/2-x) = sinx

Answer 3

yeah i know but i'm confused cuz theres a ^2 :/

Answer 4

does it become sin^2 ?

Answer 5

sure, for the numerator be sin^2 x

Answer 6

so then i get sin^2x / cosx

Answer 7

yeah, = sinx * sinx/cosx, right ?

Answer 8

yes