Question

Find all solutions in the interval [0, 2π).

sin2 x + sin x = 0

pleaseee

Answer 1

sin2x=-sinx
I believe this only happens when sin(x)'s are equal to zero.
So your answers would be 0, pi

Answer 2

thats not one of the answers.. theyre 0,π, π/3, 5π/3
0,π,π/3,2π/3
0,π,4π/3,5π/3
0,π,3π/2

Answer 3

Since you have a multiple choice problem, I would just plug the possible values they give you into the equation and see if they work.

Answer 4

Factor out a sin(x) giving:
\[\sin(x)(\sin(x)+1)=0 \implies \sin(x)=0 or \sin(x)=-1 \implies\]\[ x=n \pi, x= \frac{3\pi}{2},\frac{7 \pi}{2}, \frac{11 \pi}{2}\]
So on \[[ 0, 2 \pi) \implies x=0,x=\pi,x=\frac{3 \pi}{2}\]

Answer 5

omg thanks so much