OpenStudy (anonymous):

factor: 128x^5+54x^2y^3

5 years ago
OpenStudy (zehanz):

This one is easier than the last one, becuase there are only two terms. Can you see numbers that are factors of both terms, 128x^5 and 54x^2y^3?

5 years ago
OpenStudy (anonymous):

ok and no.... im really bad at these....... :/

5 years ago
OpenStudy (zehanz):

128 = 2*64, 54 = 2*27 So 2 is a factor of 128 and of 54. This means you could write it as$2(64x^5+27x^2y^3)$ But I can see more common factors now...(hint: x)

5 years ago
OpenStudy (anonymous):

i figured it out thank you!!

5 years ago
OpenStudy (zehanz):

$2x^2(64x^3+27y^3)$

5 years ago
OpenStudy (anonymous):

thats what i got thank you tons!! :)

5 years ago
OpenStudy (zehanz):

YW ;)

5 years ago