Question

Find the slope of the tangent line to the graph of f at the given point.

f(x) = root2 at ( 36, 6)

Answer 1

Would it be 12?

Answer 2

No, somehow I am getting 6.

Answer 3

\[f(x)=x^{\frac{1}{2}}\\f(x)'=\frac{1}{2}x^{\frac{1}{2}-1}=\frac{1}{2\sqrt{x}}\]

Answer 4

so is the answer 1/3

Answer 5

no, it's D.

\[f(6)'=\frac{1}{2\sqrt{36}}=\frac{1}{12}\]