Calculate the equation of the line that passes throught the points (1,5) and (3,6)
Do you know the general equation for lines?
we have been using the equations y+a(x-h)+k or y=(x-h)+k
I answered a similar question a while ago: http://openstudy.com/study#/updates/50cbc57de4b0031882dbd6c4 Now that I think about it I answer this every once in a while on Open Study. Maybe the teachers should do a better job explaining... o_0
thank you i think i know what im doing now(:
If we want to use that equation, I would insert one point in for (h, k) and solve for a by substituting in the other as (x, y). y = a(x - h) + k We can let (h, k) be either point and (x, y) be the other point, it seems. We then just solve for the value of a to use in the equation.
okay thank you (:
You're welcome! :)
i have one other question, how do you calculate the slope and distance between a line?
Hmm... could you explain the "distance of a line"? As in, the distance between a line and a point? Or between two points on the line? Slope is just calculated as the ratio of the differences in y values and x values of two points on a line. Or in other words, how much it 'rises' over how much it 'runs. m = (y2 - y1)/(x2 - x1) from two points (x1, y1) and (x2, y2)
the distance between two points like from point to point
The general formula of the distance between two points is just \( \displaystyle d = \sqrt{ (x_2 - x_1)^2 + (y_2 - y_1)^2} \) It comes from Pythagorean theorem, where the graph is like this: |dw:1355536836024:dw|
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