Question

Trapezoid Rule Help?
See below.

Answer 1

\[\int\limits_{1}^{2} \frac{ 1 }{ (x+1)^2 }\]

Answer 2

@sirm3d

Answer 3

wait...

Answer 4

trapezoidal rule with \(x_0=a\) and \(x_n=b\)\[\int\limits_{1}^{2}\frac{ 1 }{ (x+1)^2 }dx=\left( f(2)-f(1) \right)\frac{ 2-1 }{ 2n }+\left( f(x_1)+f(x_2)+\cdots +f(x_{n-1}\right)\frac{ 2-1 }{ n }\]

Answer 5

with \[f(x) = \frac{1}{(x+1)^2}\]you choose the number of intervals by specifying a value for \(n\), like \(n=10\).

Answer 6

oh shoot n = 4

Answer 7

his is the work that they have, but i don't understand where they got the 5/4 from cuz the subintervals are 1/2,1,3/2,and 2...

Answer 8

1=1
1+1/4=5/4
1+2/4=6/4=3/2
1+3/4=7/4
1+4/4=2

Answer 9

oh is it a rule to add the lower limit (1) to the subintervals?
but i got 1/2 as the subintervals...

Answer 10

you are going from 1 to 2 not 0 to 2

Answer 11

oh my bad, i cannot divide...

Answer 12

yeah i got it....

Answer 13

@jkp269