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x^(-1/2)=1/2 how can you get the x alone?
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\[\frac{1}{\sqrt{x}}=\frac{1}{2}\iff \sqrt{x}=2\iff x=4\]
knowing that \(x^{-r}=\frac{1}{x^r}\) and that \(x^{\frac{1}{2}}=\sqrt{x}\)
i understand. how do you get the 2 in the second step?
do you multipy by two? and if so would that not take away the square root?
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Or the logarithm trick would work...
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