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MIT 18.01 Single Variable Calculus (OCW)
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How come we can turn (((1 / (x + h)) - (1 / x)) / h) into ((1 / h) * ((x - (x + h)) / (x + h) * x)) I don't understand the steps in between the two.
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The question is why \[\frac{ \frac{ 1 }{ x+h } + \frac{ 1 }{ x } }{ h } = \frac{ 1 }{ h } * \left[ \frac{ x - (x+h) }{ (x+h) * x } \right] \] Answer: \[\frac{ \frac{ 1 }{ x+h } - \frac{ 1 }{ x } }{ h } = \frac { 1 }{ h } * \left[ \frac{ 1 }{ x+h } - \frac{ 1 }{ x } \right] \\ = \frac { 1 }{ h } * \left[ \frac{ 1 * x }{ (x+h) * x } - \frac{ 1* (x+h) }{ x * (x+h) } \right] \\ = \frac { 1 }{ h } * \left[ \frac{ x }{ (x+h) * x } - \frac{ (x+h) }{ (x+h) * x } \right] \\ = \frac { 1 }{ h } * \left[ \frac{ x - (x+h) }{ (x+h) * x } \right]\]
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