Find the exact value of the trig function given that sin u=5/13 and cos v=-3/5. Both u and v are in the quadrant II: sin (u+v)

Question

tamtoan · Answer

use the formula for sin(u+v) ...you have everything given

anonymous · Answer

So I would just do sin ((5/13) + (-3/5))?

tamtoan · Answer

no, it's in quadrant 2, and you can draw the circle of where you can locate that angle with the sine and cosine given to you. sine = y coordinate and cosine = x coordinate ..then use the formula sin(u+v) = sin(u)cos(v) + sin(v)cos(u)

anonymous · Answer

Would you be in radian or degree mode for this?

tamtoan · Answer

something like this ...for cos(v) = -3/5

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figure out sine ..then do the same with the other angle.