Question

find the domain
y=f(x)=x^2-6x+6

Answer 1

domain means the values which 'x' can take in that equation.

Answer 2

do u see any values that 'x' can't take ?

Answer 3

i dont get it......??

Answer 4

(1)there is no denominator, if there was, then 'x' could not take values for which denominator=0

Answer 5

so ther is no soln for this??

Answer 6

(2) there is no \(\sqrt.\) sign, if there was , then 'x' cannot take values for which the expression under \(\sqrt{...}\)becomes negative.

Answer 7

here, none of the 2 cases (1) or (2) arise.
so 'x' can take all real values.

Answer 8

so, domain is ALL real numbers R

Answer 9

understood ?

Answer 10

sorry i quite didnt get it

Answer 11

which par ?

Answer 12

x belongs to R
then can we supoose any no we want in the place of x??

Answer 13

yes, x can take any real value.
u have options/choices ?

Answer 14

how wud u solve this prob?

Answer 15

example : f(x) =1/ x
x cannot take value =0
f(x) = 1/(x-3)
x cannot take value = 3
f(x) = sqrt{x-4}
x cannot take value less than 4

Answer 16

can u be mo` specific...?i cant understand

Answer 17

i just gave u specific examples.
and there's nothing to solve, you can say 'x' can take all real values...

Answer 18

y did u add -3 in da denominator?

Answer 19

By the way, all polynomials have the domain \((-\infty,\infty)\) a.k.a \(\mathbb{R}\).

Answer 20

can u do the whole process??

Answer 21

Domain means whenever the function exists. To figure this out, just find when the function does not exist, meaning when you're dividing by 0. In this case, you're never dividing by 0, so the function ALWAYS exists, so the domain is ]-inf,inf[, also know as "R" for all real numbers.

If say f(x) = 1/(x-4), then the domain is ]-inf,-4[U]-4,inf[, because the function exists everywhere except at x=-4.