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Chemistry 17 Online
OpenStudy (anonymous):

4. Carotene, the pigment responsible for the color of carrots, has a percent composition of 89.49%--C and 10.51%--H. Its molecular mass was found to be 546.9g. Calculate its empirical formula and its molecular formula.

OpenStudy (abb0t):

Assuming 100% composition you would take 0.8949g of carbon and 0.1051 g of hydrogen. You then take the molecular mass given to find moles.

OpenStudy (anonymous):

ok so Carbon has .0745 mol and hydrogen has .1043 mol. now what do i do?

OpenStudy (anonymous):

so would the units be g/mol?

OpenStudy (abb0t):

Divide the mol given by 0.745 for both.

OpenStudy (abb0t):

0.0745*

OpenStudy (anonymous):

so not by the molecular mass?

OpenStudy (abb0t):

No. That's for molecular formula. Sorry.

OpenStudy (abb0t):

like information to osrt of "check"

OpenStudy (anonymous):

okay so i got 1 for carbon and 1.4 for hydrogen

OpenStudy (abb0t):

ok, round to the closest whole number ratio and that's your empirical formula

OpenStudy (anonymous):

okay so what about the molecular formula? and so the empirical formula would be just 1 and 1?

OpenStudy (abb0t):

Find the total mass of your empirical formula and divide that total by your molecular mass found out.

OpenStudy (abb0t):

You should have: \[\frac{ 546.9g }{ 13.018g }\]

OpenStudy (anonymous):

how did you get 13.018?

OpenStudy (abb0t):

Well, your empirial formula give is CH. The total mass of C + H = 13.018 g/ mol

OpenStudy (anonymous):

okay so the answer to 546.9g/13.018g is 42.01.

OpenStudy (abb0t):

Yep, now multiply that number by your empirical formula to get your molecular formula.

OpenStudy (anonymous):

so multiply 42.01 with 1 or 2?

OpenStudy (abb0t):

42(empirical formula)

OpenStudy (anonymous):

what is the empirical formula though? 1 or 2?

OpenStudy (abb0t):

1!

OpenStudy (anonymous):

so its just 42.01..

OpenStudy (abb0t):

Use whole numbers. So 42.

OpenStudy (anonymous):

so thats it?

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