Question

Evaluate. ArcTan( sqrt3/ 3)

Answer 1

\[\tan^{-1} \frac{ \sqrt{3} }{ 3 }\]

Answer 2

Let \(\theta\) be \( \tan^{-1} \dfrac{\sqrt{3}}{3} \).

\(\tan \theta = \dfrac{\sqrt{3}}{3}\)

At what angle is \(\tan \theta\) equal to \( \dfrac{\sqrt3}{3} \)?

Answer 3

It's 30. But I don't know how I got that.

Answer 4

Well, \(\tan 30^{\text{o}} = \dfrac{\sqrt3}{3}\) so it's true that \(30^{\text{o}} = \tan^{-1}\dfrac{\sqrt3}{3}\).

Answer 5

I thought Tangent was opposite over adjacent.

Answer 6

OH THEY RATIONALIZED IT

Answer 7

It is.

Welcome.

Answer 8

God damn it, tricky bastards. >:|
Thanks a lot. xD