Question

i cant verify 1+cos2x / sin2x = cotx....HELP

Answer 1

it should be (1+cos2x)/sin2x

Answer 2

\[1+\cos2x=2 \cos ^{2}x\]
and sin2x =2 sinx cosx

Answer 3

\[\frac{ 1+\cos2x }{ \sin2x } = cotx\]

Answer 4

\[1+\cos2x=2\cos ^{2}x\]
and sin2x=2sinxcosx
substitute these two to get the answer

Answer 5

cosx/sinx=cotx

Answer 6

so it becomes like \[\frac{ 2\cos^2x }{ 2sinxcosx }\]

Answer 7

???

Answer 8

but what do i do after that?

Answer 9

cancel the common terms.
then cosx/sinx=cotx

Answer 10

so it then becomes 2cosx / 2sinx

Answer 11

and the twos cancels out...so it becomes cosx / sinx!! thank you!

Answer 12

ok! remember to close the question guys and if appropriate, to award medals:)