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If \(\Large{a^x=b^y=c^z}\) then \(\Large{b^z=ac}\) then \(y=?\)
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ehh... oh jees this isn't that fun. logs ;)
Are u saying this to me @RONNCC ??
\[Ans. \frac{2xz}{x+z}\]
Take a^x=b^y=c^z = k
ok
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@jiteshmeghwal9 is it b^2 = ac or b^z = ac
b^z=ac
b^y = c^z b=c^(z/y) Now, b^z =ac (c^(z/y))^z =ac c^(z^2/y) =ac c^(z^2/y -1)=a c^(z^2/y -1) = c^(z/x) z^2/y -1 = z/x y=(xz^2)/(x+z)
Yup..thats wat i got
@jiteshmeghwal9 it shuld be b^2 = ac
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then a , b c are in G.P
u mean geometric progression
thanx i gt it :)
(k^1/y)^2 = k^(z+x)/xz 2/ y = (z+x) / xz y = 2xz / x+z
thanx both of u @Yahoo! @sauravshakya :)
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Yup..Probably the question is Wrong
Welcome...:)
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