Question

anyone good at synthetics? from alg 2 Help anyone?

Answer 1

please help me

Answer 2

do you have a specific question?

Answer 3

ya its (2t^2+13t+15) divided by (t+5)

Answer 4

Start by writing out the coefficients in a table and write the test root (-5) off to the left like this

-5 | 2 13 15
|
------------------------------

Answer 5

Pull down the first coefficient 2

-5 | 2 13 15
|
------------------------------
2

Answer 6

Multiply the test root (-5) with 2 to get -10, write this under the 13

-5 | 2 13 15
| -10
------------------------------
2

Answer 7

i did that

Answer 8

Add 13 to -10 to get 3. Write this under the -10


-5 | 2 13 15
| -10
------------------------------
2 3

Answer 9

Repeat the last two steps

-5 | 2 13 15
| -10 -15
------------------------------
2 3 0

Answer 10

The last line is 2 3 0

so (2t^2+13t+15) divided by (t+5) = 2t+3 remainder 0

Answer 11

Since the remainder is 0, t+5 is a factor of 2t^2+13t+15

ie

2t^2+13t+15 = (t+5)(2t+3)

Answer 12

ok thanks

Answer 13

np

Answer 14

can you help me with a few more problems if i get stuck?

Answer 15

sure just a few though

Answer 16

ok thanks