9. An object is fired straight up from the top of a 200-foot tower at a velocity of 80 feet per second. The height, h(t) of the object t seconds after firing is given by h(t) = -16t^2 + 80t + 200. A. Find the maximum height reached by the object and the time that the height is reached. B. Interpret the meaning of the y-intercept in the context of this problem.
If you were to graph it on your calculator (or wolfram) the answer to A. is the y value at the maximum point.
y-intercept you have to think about it. that is at time 0. Right?! Because the y-intercept is when x=0. So at time 0 what is the height? Hint: it is the initial height
Is it 299.95473???? ????
idk I didn't do it
that number is y, but I don't think it's the y-intercept
\[h(t) = -16t^2 + 80t + 200\]\[h'(t) = -32t + 80\]\[0 = -32t + 80\]\[32t=80\]\[t=2.5\]\[h(t) = -16(2.5)^2 + 80(2.5) + 200\]\[h(t)=300\]
300 is the answer to A
reread my initial post for B
It says it need the height and the time
hate to say it but 300 is an exact answer. I don't know how wolfram got its 299.whatever The time is the x value.
wolframalpha got 300; t = \[\frac{ 5 }{ 2 }\]
which is 2.5, which is what I got. See how quick calculus is?!
I want to make sure you are understanding. Do you know why time is the x-value and height is the y value?
explain it real quick
\[h(t) = -16t^2 + 80t + 200\]h stands for height in this problem. and h depends on t. That's what h(t) means. You say it as "h of t". Means height changes as t changes. t stands for time. say we had our finger on the x-axis and moved it to the right. we are increasing the time which is increasing the height on the y-axis. did this help
I should have probably said changing the height as time changes, because the height goes up then back down
okay I get it now partially
just remember that h(t) or f(x) or anything of anything is usually always referring to the y-axis. and the of something or t or x is the x-axis
I am pretty sure we'll get more in to that later in the year maybe
definitely
Good luck
are you sure we'll learn it in Algebra2
definitely
What was your initial post for B
the initial height is the height of the beginning. That is at time zero
building not beginning
A is 300 - maximum height and 5/2 - t(time) B was what???
height of the building.
so is B the height of the building
You know what @ChmE
Thanks a whole lot man I hope you can help me out later sometime! :D
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