Question

y=2-x, x(x+y)=5-3y^2 a solution would be helpful please, no idea how these things are solved

Answer 1

You know that y=2-x, so plug in 2-x instead of y in the second equation and solve.

Answer 2

Hold on, lemme try

Answer 3

What's (2-x)^2?
Is it the long answer or like, the one with 2 numbers?

Answer 4

can't do it man, help me out here

Answer 5

If y = 2-x, then x = 2-y. Replace each x with 2-y

Answer 6

where do I go from 2-2y=5-3y^2?

Answer 7

Put it in the standard form for a quadratic equation and then solve by factoring (if it will factor) or by the quadratic formula if it will not.

Answer 8

English man, English

Answer 9

Rearrange the equation so that it is equal to 0. Make the y^2 term positive.

Answer 10

Also, it should be 4-2y not 2-2y

Answer 11

Oh

Answer 12

Actually, Mertsj is right, it's easier to replace x other than y.

Answer 13

Eh?

Answer 14

could one of you dudes just give me the answer +solution? It's REALLY late

Answer 15

\[(2-y)(2-y+y)=5-3y^2\]
\[(2-y)(2)=5-3y^2\]
\[4-2y=5-3y^2\]
\[3y^2-2y-1=0\]
\[(3y+1)(y-1)=0\]

Answer 16

Can you solve that for y?

Answer 17

waaaait

Answer 18

how did 3y^2-2y-1=0 become (3y+1)(y-1)=0
?

Answer 19

By factoring.

Answer 20

what method?

Answer 21

You can also use discriminant if you want.

Answer 22

Too many cooks.

Answer 23

mmm, well

Answer 24

thanks dudes, I'll try to figure this dang thing out

Answer 25

Sorry Helper
Can't give more than one medal