Question

9^8x = 27 How do you do this? I converted it to log base 9 of 27 = 8x but that didn't really help me.

Answer 1

I notice that 9 is 3^2 and 27 is 3^3
so replace 9 with 3^2 and 27 with 3^3

Answer 2

\[ (3^2)^{8x} = 3^3 \]

Answer 3

What do you do after that? Sorry I really don't get logs.

Answer 4

I would use the rule
\[ (x^a)^b= x^{ab} \]
to rewrite the left side
then notice that you have the same bases on both sides. I would think the exponents must equal each other for the equation to be true.

or take the \(\log_3 \) of both sides

Answer 5

Thanks, that helped a lot for all of my log problems!

Answer 6

for this problem you should get 16x =3 and x= 3/16

Answer 7

this is another way to do it