How would I solve this?
http://curriculum.kcdistancelearning.com/courses/ALG1x-HS-A06/a/exams/3-EXAM3/778.gif

Question

How would I solve this?
http://curriculum.kcdistancelearning.com/courses/ALG1x-HS-A06/a/exams/3-EXAM3/778.gif

anonymous · Answer

2b/4+b/3=10 is very easy

anonymous · Answer

multiple two side of equation in 3 and 4

anonymous · Answer

i try to multiple to 4:
4 (2b/4+b/3=10 ) =
2b+4b/3=40

anonymous · Answer

do you multiple in 3..

anonymous · Answer

so for 3 would i do what you did for 4?

anonymous · Answer

i would multiply both sides by 12 to clear the fractions on the left

anonymous · Answer

@satellite73  so how would i get that 12??

anonymous · Answer

oh i got it now thanks guys B= 12

anonymous · Answer

$$12\times \left(\frac{2b}{4}+\frac{b}{3}\right)=12\times 10$$
$$6b+4b=120$$
$$10b=120$$ $$b=12$$

anonymous · Answer

yes, $b=12$

anonymous · Answer

of course you could start with the fact that $\frac{2b}{4}=\frac{b}{2}$ and then multiply both sides by $6$
either way

anonymous · Answer

your welcome