Question

How would I solve this?
http://curriculum.kcdistancelearning.com/courses/ALG1x-HS-A06/a/exams/3-EXAM3/778.gif

Answer 1

2b/4+b/3=10 is very easy

Answer 2

multiple two side of equation in 3 and 4

Answer 3

i try to multiple to 4:
4 (2b/4+b/3=10 ) =
2b+4b/3=40

Answer 4

do you multiple in 3..

Answer 5

so for 3 would i do what you did for 4?

Answer 6

i would multiply both sides by 12 to clear the fractions on the left

Answer 7

@satellite73 so how would i get that 12??

Answer 8

oh i got it now thanks guys B= 12

Answer 9

\[12\times \left(\frac{2b}{4}+\frac{b}{3}\right)=12\times 10\]
\[6b+4b=120\]
\[10b=120\] \[b=12\]

Answer 10

yes, \(b=12\)

Answer 11

of course you could start with the fact that \(\frac{2b}{4}=\frac{b}{2}\) and then multiply both sides by \(6\)
either way

Answer 12

your welcome