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Evaluate 6^(log14/log6)
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any guesses for this one?
I used log rules but I didn't get the right answer. I tried to go log base of 6 with 0= log14/log6 as well.
by definition \[b^x=e^{x\log(b)}\] so \[6^{\frac{\log(14)}{\log(6)}}\] \[=e^\frac{\log(14)}{\log(6)\times \log(6)}\] \[=e^{\log(14)}=14\]
ok i made a typo on line 3 above
thanks, 14 is the right answer!
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\[e^{\frac{\log(14)}{\log(6)}\log(6)}=e^{\log(14)}=14\]
yw, sorry about the typo
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