Segment LM is the midsegment of trapezoid ABCD. AB= x + 8, LM = 4x + 3, and DC = 187. What is the value of x?
The length of the midsegment is the average o f the lengths of the two bases. LM = (AB + CD)/2 Substitute what you are given for LM, AB and CD and solve for x.
(x + 8 + 187) / 2? Is this the next step?
Good so far. That is equal to what?
use this formula 1/2*(sum of parallel side) * distance between them
Then, where does that get me?
not really, because i missed half a semester of this stuff and none of it makes sense.
From the top again: (x + 8 + 187)/2 = 4x + 3 Multiply both sides by 2: x + 8 + 187 = 2(4x + 3) Add numbers on left side, distribute oin right side: x + 195 = 8x + 6 Subtract 8x from both sides: -7x + 195 = 6 Subtract 195 from both sides: -7x = -189 Divide both sides by -7: x = 27
Totally makes sense now, thank you.
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