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Mathematics 16 Online
OpenStudy (anonymous):

Please help. Will give medal.

OpenStudy (anonymous):

kk, what is it?

OpenStudy (jiteshmeghwal9):

Yup, plz tell us wht's ur question ?

OpenStudy (hba):

@Atowe3006 Sure,What is the question mam ?

OpenStudy (anonymous):

\[-9m ^{-2}n ^{5}*2m ^{-3}n ^{-6}\]

OpenStudy (anonymous):

You merely add exponents of like bases:\[-18m ^{-5}n ^{-1}\]and multiply the numerics.

OpenStudy (hba):

Let me clear the point, \[\huge\ a^x * a^y=a^{x+y}\]

OpenStudy (anonymous):

Would it be a fraction?

OpenStudy (anonymous):

Since there is negatives?

OpenStudy (anonymous):

So, for the base "m", you add -2 and -3 to get -5. You could represent it as a fraction.\[\frac{ -18 }{ m ^{5}n }\]

OpenStudy (anonymous):

Yes, because the exponents are negative, they can go into the denominator.

OpenStudy (anonymous):

Thank you so much, Can you please help me with some others? I keep watching the video my teacher gave us to watch but I barely understand it.

OpenStudy (anonymous):

Good luck in all of your studies and thx for the recognition! @Atowe3006 I'll try to help with more. And you are welcome very much!

OpenStudy (anonymous):

3. A rectangular pasture has a fence around the perimeter. The length of the fence is \[16x ^{7}\] and the width is \[48x ^{4}\]. What is the area of the pasture? (1 point)

OpenStudy (anonymous):

And no problem (:

OpenStudy (anonymous):

and 21,504 isn't an answer.

OpenStudy (anonymous):

np. A(rea) = (l)(w) =\[(16x^{7})(48x ^{4}) = 768x ^{11}\]where you add the 4 and 7 for the like base "x" and just multiply 16 by 48.

OpenStudy (anonymous):

Oh!!! Omfg that was so blonde of me. Hah hah! I really appreciate you helping.

OpenStudy (anonymous):

We all have little slip-ups. I do them all the time!

OpenStudy (jiteshmeghwal9):

\((-9*2)m^{-2}.m^{-3}.n^5. n^{-6}\)

OpenStudy (jiteshmeghwal9):

\(\LARGE{-18m^{-2+(-3)}.n^{5+(-6)}}\)

OpenStudy (anonymous):

A good way to remember that you add exponents for like bases when multiplying is from the following simple example:\[2^{2}2^{3} = (4)(8) = 32 = 2^{5}\]If you can reconstruct that when you have a "blonde" moment, you'll do great!

OpenStudy (jiteshmeghwal9):

i think u can solve it further

OpenStudy (anonymous):

Thank you!!!

OpenStudy (anonymous):

you're welcome!

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