Joe traveled to the town hall and back. It took 3 hours long to go there than it did to come back. The average speed on the trip was 30km/h. The average speed on the way back was 75km/h. How many hours did the trip there take?

Question

hero · Answer

d = rt
To get there, it takes three hours longer so in other words, three hours slower:
d1 = 30(t - 3)
Coming back, it is three hours quicker:
d2 = 75t

No matter how slow or fast the trip, the distance to and from two two specific locations will always be the same, so:

d1 = d2
30(t - 3) = 75t

Solve for t

anonymous · Answer

Thank you!!

hero · Answer

Did you solve for t yet?

anonymous · Answer

So far i got 30t-90= 75t then 30 and 75 which would be 135t................. and i think i did it wrong

hero · Answer

Actually, after further investigation, the formula should be

30(t + 3) = 75t

anonymous · Answer

uh explain please

hero · Answer

Well, basically, t represents how long, in hours, it will take to travel to get from A to B. Since getting there takes longer, it will take t + 3 hours.

anonymous · Answer

So then wouldn't you distribute the 30 to the T and the +3