...never got help so im reposting
|dw:1358469689716:dw|
You have to work out weather path ABC or ADC is shorter. path ABC = AB + BC path ADC= AD + DC you can use Pythagorus's theorem to calculate AB and (DC)
yeah i know im getting sqrt(40) for A to B and 6 for B to C
B is the correct answer but i can't get the exact distance from A to B and then from B to C
@UnkleRhaukus you there?
sorry i got distracted, you've got AB right and you've got BC right too
how would i put the answer in a website? i think thats what im doing wrong.
@satellite73 can you assist me here too please
you want the total distance right? do you know the shortest rout?
yes / B is the shortest
from A to B is \(\sqrt{2^2+6^2}=\sqrt{40}\) and from B to C is 6
ok. how would i put that in on a hw website?
so that distance total is\[6+\sqrt{40}\]
i have no idea maybe it wants a decimal
\[\sqrt{40}=\sqrt{4\times10}=\sqrt{2^2\times2\times5}=2\sqrt{2}\sqrt{5}\]
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