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OpenStudy (anonymous):
OpenStudy (unklerhaukus):
|dw:1358469689716:dw|
OpenStudy (unklerhaukus):
You have to work out weather path ABC or ADC is shorter.
path ABC = AB + BC
path ADC= AD + DC
you can use Pythagorus's theorem to calculate
AB and (DC)
OpenStudy (anonymous):
yeah i know
im getting sqrt(40) for A to B
and
6 for B to C
OpenStudy (anonymous):
B is the correct answer but i can't get the exact distance from A to B and then from B to C
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OpenStudy (anonymous):
@UnkleRhaukus you there?
OpenStudy (unklerhaukus):
sorry i got distracted,
you've got AB right and
you've got BC right too
OpenStudy (anonymous):
how would i put the answer in a website? i think thats what im doing wrong.
OpenStudy (anonymous):
@satellite73 can you assist me here too please
OpenStudy (anonymous):
you want the total distance right? do you know the shortest rout?
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OpenStudy (anonymous):
yes / B is the shortest
OpenStudy (anonymous):
from A to B is \(\sqrt{2^2+6^2}=\sqrt{40}\) and from B to C is 6
OpenStudy (anonymous):
ok. how would i put that in on a hw website?
OpenStudy (anonymous):
so that distance total is\[6+\sqrt{40}\]
OpenStudy (anonymous):
i have no idea
maybe it wants a decimal
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