Question

A circle of radius 3 is centered at the origin and passes through the point .(2,sqrt5)
(a) Find an equation for the line through the origin and the point .


(b) Find an equation for the tangent line to the circle at . (2,sqrt5)

Answer 1

1) Find the slope line going through \((0, 0)\) and \((2,\sqrt{5})\)
2) The slope of a perpendicular line is just the negative reciprocal.

Answer 2

once you have the slopes of each you can use point slope formula

Answer 3

if it is centered at the origin and has radius 3, then the equation must be \(x^2+y^2=9\)

Answer 4

if you can use calculus, this is easy
if not you do what @wio said

Answer 5

actually @wio answer is easiest nvm