Question

rationalize the denominator

Answer 1

\[\frac{ \sqrt{11}+\sqrt{2} }{ \sqrt{11}-\sqrt{2} }\]

Answer 2

working..

Answer 3

\[\frac{ \sqrt{11}+\sqrt{2} }{ \sqrt{11}-\sqrt{2} }\times \frac{ \sqrt{11}+\sqrt{2} }{ \sqrt{11}+\sqrt{2} }\]

Answer 4

well you need to mutiply it by 1 written in the from

\[\frac{\sqrt{11} + \sqrt{2}}{\sqrt{11} + \sqrt{2}}\]

so you problem is now

\[\frac{\sqrt{11} + \sqrt{2}}{\sqrt{11} - \sqrt{2}} \times \frac{\sqrt{11} + \sqrt{2}}{\sqrt{11} + \sqrt{2}}\]

the denominator is the difference of 2 squares... and the numberator is a perfect square... just evaluate for the solution.

Answer 5

im just confused on how to evaluate the difference of squares in the denom

Answer 6

do the square roots cancel?

Answer 7

well do the multiplication

you get

\[\sqrt{11} \times \sqrt{11} - \sqrt{2} \times \sqrt{11} + \sqrt{11} \times \sqrt{2} - \sqrt{2}\times \sqrt{2} \]

this simplifies to

\[\sqrt{11} \times \sqrt{11} - \sqrt{2}\times \sqrt{2}\]

Answer 8

this will result in a rational number denominator

Answer 9

\[11^{2}\times11^{2}-2^{2}\times2^{2}\]?

Answer 10

nope its

\[(\sqrt11)^2 - (\sqrt{2})^2\]

Answer 11

ah so 11-2=9?

Answer 12

i think i will skip the question and find the material, thanks for your time sir

Answer 13

yep the denominator is 9... all you need to do is simplify the numerator