Without using a calculator, find the matching value for f in each function. Give exact answers.
\[f=\cos (-\frac{ 3\pi }{ 2 })\]
find the point on the unit circle corresponding to the angle of \(-\frac{3\pi}{2}\) cosine will be the first coordinate
thats 300 degrees and the first coordinate is 1/2 but thats not the correct answer...:/
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oh oh oh i was looking at the coordinates of y
so its 270 degrees.
forget degrees. angles measure in radians you should be right at the top of the circle at \((0,1)\)
At the top of my circle i have pi/2...
yes that is true, but if you go around the circle in the negative direction (clockwise) then you end up at the same point
but how does that change it? you end up at the same place...
hope that is clear count in units of \(\frac{\pi}{2}\) going the other direction
you do end up in the same place, so the cosine is 0 and the sine is 1
in other words \(\cos(\frac{\pi}{2})=\cos(-\frac{3\pi}{2})\)
both sine and cosine are periodic with period \(2\pi\)
okay, okay i can see that cause if the bottom of the circle is 3pi/2 that the opposite of that would be negative. AKA the upper half of the circle. okay...
or just count, either way
okay it just kinda had to click in my brain.. so f=cos(-3pi/2) is the exact same thing as f=cos(pi/2)
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