Could someone please help? I do not think I'm doing this right :( or maybe I am missing steps. This question is multiple choice but I am not sure how to get it to look like the answer choices.
Solve. 2x^2-8x-12=0

Question

Could someone please help? I do not think I'm doing this right :( or maybe I am missing steps. This question is multiple choice but I am not sure how to get it to look like the answer choices. 
Solve. 2x^2-8x-12=0

aravindg · Answer

ok so here you have to solve the quadratic

anonymous · Answer

Like this? 2x^2-8x-12=0
                     +8x+12x  +8x+12x
              2x^2+8x+12x=8x+12x

aravindg · Answer

use the quadratic formula to get value for x

ie for a quadratic $ax^2+bx+c$

$$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$$

aravindg · Answer

*

$$ax^2+bx+c=0$$

anonymous · Answer

x^2=4x+6?

nubeer · Answer

$$x= \frac{ -b \pm \sqrt{? b^{2} -4ac}}{ ? }$$
in your question  2x^2-8x-12=0
a=2, b = -8, c =-12 .... just plug in values u will get 2 answers.

nubeer · Answer

sorry seems like i missed 2a in denominator.. sorry

aravindg · Answer

lols :P

aravindg · Answer

well after you divide by 2 you will get 

$$x^2-4x-6=0$$

aravindg · Answer

ok use quadratic formula now

anonymous · Answer

x=-8±√(8^2-4(2)(12)/4)

aravindg · Answer

a=1 , b=-4 ,c=-6

aravindg · Answer

look at the values above ^

aravindg · Answer

substitute it in quadratic equation

aravindg · Answer

@P.nut1996  do it !

anonymous · Answer

My answer choices are  x = 1 ± 2

 x = 2 ± 

 x = 2 ± 

 x = 2 ± 2

aravindg · Answer

what did u get after applying quadratic formula?