Question

3(1+x)^1/3 - x(1+x)^-2/3 / (1+x)^2/3

I need help. Please show steps please?

Answer 1

\[3(1+x)^{2/3}-x(x+1)^{-2/3}/(1+x)^{2/3}\]

Answer 2

they cant show the negative in x(x+1)^-2/3. can anyone please help me solve it?

Answer 3

\[3(1+x)^{\frac{2}{3}}-\frac{x(x+1)^{-\frac{2}{3}}}{(1+x)^{\frac{2}{3}}}\]

Answer 4

\[3(1+x)^{\frac{ 2 }{ 3 }}-\frac{ x(x+1)^{-\frac{ 2 }{ 3 }} }{ (1+x)^{\frac{ 2 }{ 3 }} }\]
=\[\frac{ 3(1+x)^{\frac{ 2 }{ 3 }+\frac{ 2 }{ 3 }}-x(x+1)^{-\frac{ 2 }{ 3 }} }{ (1+x)^{\frac{ 2 }{ 3 }} }\]

Answer 5

That is correct so far.

Answer 6

sorry if you misunderstood, but the whole thing is divided by (1+x)^2/3. sorry if that was not clear.

Answer 7

AH okay. @Mertsj You do that for @asapbleh

Answer 8

I'm going to take a rest.

Answer 9

\[3(1+x)^{-\frac{1}{3}}-x(1+x)^{-\frac{4}{3}}=(1+x)^{-\frac{4}{3}}[3(1+x)^{\frac{3}{3}}-x]\]

Answer 10

\[(1+x)^{-\frac{4}{3}}(3+3x-x)=(1+x)^{-\frac{4}{3}}(3+2x)\]

Answer 11

What were you supposed to do with this?

Answer 12

It was a homework problem. it says "simplify the expression. (This type of expression arises in calculus when using the quotient rule."

Answer 13

There are several different forms you could put it in. That one is probably as good as any.

Answer 14

ok, thankyou very much!

Answer 15

yw