Question

Can someone check my answer?

Answer 1

\[1+\sec^2\times \sin^2=\sec^2\]

Answer 2

\[1+\frac{ 1 }{ \cos }\times \frac{ 1 }{ \cos }\times \sin^2\]

Answer 3

go on

Answer 4

\[1+\frac{ 1 }{ \cos }\times \frac{ 1 }{ \cos }\times \frac{ \sin }{ 1 }\times \frac{ \sin }{ 1 }\]

Answer 5

goin good:)

Answer 6

\[1+\frac{ \sin }{ \cos }\times \frac{ \sin }{ \cos }\]

Answer 7

\[1+\tan^2\]

Answer 8

correct :)

Answer 9

\[\sec^2=\sec^2\]

Answer 10

thank you!

Answer 11

np :)