Find the cube roots of 125i, using the method of finding nth cube roots.... I need help in knowing how to tell what the angle is.
|dw:1359988079100:dw| since on the complex plane maginary no are either on positive y axix or negative y axis depends on the sign of imaginary part .since 125i is posive and has real part zero so it will be along imaginary axis (along positive y axis ) the angle corresponding to this must be pi/2 .
@sami-21: Excuse me, can you explain me clearer. I have problem with this, too. and, if we scale the y axis, I mean the imaginary part, which point can we represent that number
ok let me try
my problem is with the formula we have to use, see to me an angle of pi/2 implies that there would be 4 cube roots while clearly there is 3 cube roots
@Edutopia you mean it must be cube roots, so is it 2pi/3
not nessicarly...
|dw:1359989008865:dw| you can see on the y axis (which is called imaginary axis is correcponding to the angle 90 or pi/2 ) . no matter what is the constant factor if its pure positive imaginary there angle will be pi/2 for example i , 5i ,40i, 50i, 70i,90, 150i, 125i , all have angle of pi/2 . while all the following (negative ) -i,-5i,-20i,-30i-100i, -125i .......... all have angle of -pi/2 .
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