Question

What is the difference in simplest form?

Answer 1

\[\frac{ n^2 + 3n + 2 }{ n^2 + 6b + 8 } - \frac{ 2n }{ n + 4 }\]

Answer 2

@cgreenwade2000 help please ?

Answer 3

You can't add or subtract fractions with different denominators.

Answer 4

@cgreenwade2000 so i should factor out the first denominator ?

Answer 5

\[\frac{ 1 }{ 6 } + \frac{ 2 }{3 } \]

What one would you change there?

Answer 6

2/3

Answer 7

to 4/6

Answer 8

If you factor the first, it doesnt turn it into n+4. Instead, multiply the second fraction by something to make the denominators the same.

Answer 9

@cgreenwade2000 (n + 2)(n + 4) or 2( n + 4) ?

Answer 10

Which one of those turns the denominator into n^2 + 6n + 8?

You know how to do that.

Answer 11

(n + 2)(n + 4)

Answer 12

@cgreenwade2000

Answer 13

So what do you have to multiply the second fraction by?

Answer 14

@cgreenwade2000 (n + 2)

Answer 15

\[\frac{ n^2 + 3n + 2 }{ n^2 + 6b + 8 }- \frac{ 2n }{ n^2 + 6n + 8 }\]

Answer 16

But, you changed the second second fraction drastically. When you did 2/3 and changed it to 4/6 you multiplied the numerator AND denominator by 2.

You have t keep the fraction the same by multiplying the numerator and denominator by the samething.

Answer 17

So, rewrite the second fraction by multiplying the NUMERATOR and DENOMINATOR by (n+2)

Answer 18

2n (n + 2) = 2n^2 + 4n

Answer 19

OK, so now rewrite your new equation now that you have common denominators.

Answer 20

\[\frac{ n^2 + 3n + 2 }{ n^2 + 6b + 8 } - \frac{ 2n^2 + 4n }{ n^2 + 6n + 8 }\]

Answer 21

@cgreenwade2000

Answer 22

Can you solve it from there?

Answer 23

@cgreenwade2000 im kinda confused on exactly what im subtracting from what

Answer 24

How would you solve

2/5-3/5

Answer 25

= -1/5

Answer 26

How did you do that?

And when you answer the question, you'll understand how to solve your problem.

Answer 27

the denominators are the same so i just subtracted the numerators

Answer 28

^Answered your own question.

Solve your problem now.

Answer 29

\[\frac{ n^2 + 2 + 2 }{ n^2 + 6n + 8 }\] @cgreenwade2000

Answer 30

Subtract the numerators.

Answer 31

You did not subtract the numerators correctly.

2-3 is not the same as 3-2.

Order matters in subtraction.

Answer 32

n^2 + 3n + 2 - 2n^2 + 4n = 2 - 1n + 2 @cgreenwade2000

Answer 33

Subtract the n^2 terms.
Subtract the n terms.
Subtract the constants.

You are make very simple mistakes, I strongly advise more pactice with fractions and basic algebra before continuing.

Answer 34

@cgreenwade2000 n^2 - 2n^2 = 2 right

Answer 35

-2 i mean

Answer 36

Think of it as 1 something minus 2 something.

That equals -1 something. Now replace the Something with n^2

Answer 37

Just like 4x - 5x equlas -1x

The variables don't just disappear.

Answer 38

so its -n^2

Answer 39

-n^2 - n + 2

Answer 40

Yes.

and I would work throught this problem again if I were you. Just to get get a good grasp of the concepts.

Answer 41

@cgreenwade2000 but that is none of my answer choices

Answer 42

The question does not say to stop after subtracting. It says to find the answer in simplest form.

Answer 43

So The simplified denominator is n + 4 @cgreenwade2000

Answer 44

You need to factor the numerator and denominator and do some cancelling. That is as far as I can help you. But iI think you know whow to do the rest.