Someone please help? Let f(x) = x2 – 16. Find f–1(x).
if we solve the problem: y = x^2 - 16; for x, what does it look like?
and technically, there is no inverse function stated in the choices :/
I have no idea :(
we need to remember how to manipulate equation around to solve for a particular variable: y = x^2 - 16 this can be algebrated about to solve for x
What would I do first?
would you agree that we can subtract 16 from each side to start to get x all alone?
err, add 16 to each side that is
Yes so it would be y = x^2/16? So C?
y = x^2 - 16 +16 +16 ---------------- y+16 = x^2 its not C, I havent gotten to the end results yet .....
do you know how we can get the "^2" off the x?
Multiply it?
good attempt, but lets try to take the square root, or sqrt it sqrt(y+16) = sqrt(x^2) sqrt(y+16) = x this is the general construct of our inverse function we are looking for, but they like to then swap xs and ys
Ohhhhh so it's B then?
B seems the most reasonable answer to me :)
Okay thank you! I have one more like this, could you help me with it too?
i can take a look at it sure
Let f(x) = 5x + 12. Find f–1(x).
lets try the same process, but this one is simpler since we aint got to sqrt nothing y = 5x + 12 how do we solve for x so that x is all alone on one side of the equation?
- 12 from each side y = 5x + 12 - 12 - 12 y - 12 = 5x
so far so good, now to uncover the x, we should divide off that pesky looking 5 right?
Yes so.. y - 12 = 5x ---------- 5 y - 12/5 = x
I think I'm confusing myself
you did fine, lets just make sure its looks "proper" :) \[\frac{y-12}{5}=x\]
Okay the closest choice I have to that is |dw:1360095933270:dw|
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