Question

find the indefinite integral (attached). please help!

Answer 1

\[\int\limits_{}^{}(cosx - 3x^2)dx\]

Answer 2

Do you know how to integrate \(\cos x\) and \(x^2\)? You can split that integral into the sum of two integrals, each has one term.

Answer 3

ooooh i have to split it? okay

Answer 4

ok im confused x.x

Answer 5

answer ;
sinx-x^3

Answer 6

\[\int\limits_{}^{} (\cos x - 3x^2) dx = \int\limits \cos x dx - \int\limits \ 3x^2 dx\]

Answer 7

Do you know how to integrate either of the integrals on the right hand side?

Answer 8

i dont understand how to do the last one

Answer 9

Remember the `Power Rule for Derivatives`? c:

It was two steps:
~Bring the power down as multiplication.
~Decrease the power by 1.

The `Power Rule for Integration` will be the opposite, and in the opposite order.
~Raise the power by 1.
~Divide by this new power.

Answer 10

Example:\[\large \int\limits x^5\;dx \qquad = \qquad \frac{x^{(5+1)}}{5+1} \qquad = \qquad \frac{1}{6}x^6\]

Answer 11

okaaay i get that.

Answer 12

oh wait. okay x.x i was trying to do wayyy too much.

Answer 13

:o

Answer 14

Is this near the end of Calc1 for you? :o
Integrals are so much fun!!! \c:/

Answer 15

well we're in the middle of the year for calculus. so far integrals have been okay.. haha