im stuck on this problem
i need steps
what i did a=68000e^(0.035*8) 68000e^(0.28) now what?
Have you seen y=a(1+b)^x where a=original amount b=growth rate(as decimal) x=time and y=amount at given time
no i havent i ssen A=pe^rt
What about \(\large A = P\left(1+\dfrac{r}{n}\right)^{nt}\)?
yeah i seen it but i have to use the one i told you about can you help me?
i have a graphing caculator i just dont know what to do next and with e
Ok, you are doing it right. What kind of graphing calculator do you use?
TI-84 PLUS SILVER EDITION
Well, it's not that hard to calculate use this calculator! For e^(...), press 2ND (blue button) then press LN. Does it help?
okay i got 89972.82724 when i multiplied that by 68000 i got a strange answer
Well, you can round it up to 89,973 since the question wants approximate number of attendance.
68000(89972.82724)=6118152252 which is not in the answer chocies
that doesnt change answer ?
No, A = 89972.82724 since you have already multiplied e^(...) by 68000. You got about 6118152252 because you did it twice.
i dont understand whats the next steps after this a=68000e^(0.035*8) 68000e^(0.28)
we found e what do we do with it?
Multiply it with 68000.
Exactly what don't you understand? Do you know what e is, right?
Just calculate 68000 * e^(0.035 * 8)
You got it?
ok so it 89973
Yes!
A=Pe^-rt =26600e^(-0.29) i put it in the calculator and got error
That's strange, I put it in the calculator and I didn't get error...
what did you get i got error i dont understand
@jim_thompson5910
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