Question

What is the formula for writing how many combinations I can make with (A, B, C, D)?

Answer 1

it would be a+b+c=d I think

Answer 2

so 12 is the answer, is there a formula for finding it?

Answer 3

n! is the formula

Answer 4

so u have 4 letters, that means 4!=4x3x2x1=24

Answer 5

i cant have any repetition though

Answer 6

The answer is:
A
B
C
D
AB
AC
AD
BC
BD
CD
ABC
ABD
BCD
CDA
ABCD

Answer 7

well these are all the possible out comes

Answer 8

the answer says 15..

Answer 9

then u should use the C notation for combunation

Answer 10

u have to know how many repletion u have to all possibilities then u would get the right answer

Answer 11

i can't see in the question u can't have repetition. but let me analyse it for u

Answer 12

ABCD
ABDC
ACBD
ADBC

Answer 13

THESE ARE FOR THE As ok

Answer 14

The question is how many possibilities can I make with (A, B, C, D)
AB = BA
ABC = CBA

Answer 15

ABCD = ABDC = ACBD = ADBC all the same

Answer 16

now let's go for the B

Answer 17

OK BUT PUT THAT NOTATION IN THE QUESTION

Answer 18

you have to ask the right question to get the right answer

Answer 19

the question on the top of this page mean n! is the formula

Answer 20

ah ok

Answer 21

well i would use

Answer 22

\[\frac{ n! }{ (n-r)! }\]

Answer 23

according to the change in the question excluding repition

Answer 24

repetition* sorry

Answer 25

what should r be?

Answer 26

u have to make sure what the question is telling u because if the question is different then u could have another formula such as

Answer 27

\[\frac{ n! }{ (n-r)!r! }\]

Answer 28

look let me give u an example famous in text books

Answer 29

Ok the question is:

How many possibilities can you write with (A, B, C, D) where AB = BA, ABCD = BACD etc.

Answer 30

yes so is how many ways you can put the letters in order, so u reduce it by subtracting the order which is r

Answer 31

so what is "r"?

Answer 32

\[\frac{ 4! }{ (4-r)! }\]

Answer 33

the answer is 15 it is not possible

Answer 34

if u have 4 teams of basketball or football, and u want them to play against each other only once which means they do not repeat the game, how many games are played?

Answer 35

i have no idea! this isnt a data management course, i really want to just know the formula for how to calculate this

Answer 36

the answer is
A
B
C
D
AB
AB
AD
BC
BD
CD
ABC
ABD
BCD
CDA
ABCD
=
15

Answer 37

what is the formula to calculate?

Answer 38

i gave u the formula

Answer 39

but what is "r"?

Answer 40

r is the size of the group that you are choosing right?

Answer 41

how many groups of 4 can be made from a set of 6 distinct elements?

n C r, where n = 6 and r = 4

6 C 4


since nPr is simpler to calculate for me, i do (nPr)/r! = nCr

6.5.4.3
------ = 3.5 = 15 is 6C4
4.3.2

Answer 42

how many groups of 0, then groups of 1, then 2, then 3, then 4 can be made using abcd?

4C0 + 4C1 + 4C2 + 4C3 + 4C4