How do I find a and b?
I don't just want an answer... I need an explanation ...
By Pythagorean Theorem on the smallest right triangle, \[a^2+20^2=b^2\] However, using the biggest triangle, we have that \[29^2b^2=(21+a)^2\] This is now a solvable system of equations.
Alternatively, you can make a proportion using the fact that all of the right triangles are similar to one another.
That was really confusing.. @OakTree
What was? The first or second response?
Both of them...
@OakTree
For the first one, you can solve the system. Have you solved systems before?
No... I went from Algebra Support to Geometry.....
Oh! I see the mistake. In the first response, second formula, it should be 20^2 + B^2. Sorry.
Anyway, a system is when you have n variables and n equations, which allows you to solve for all of the variables.
You solve it by, in this one, taking the value for b^2 in the first equation and plugging it into the second equation. Because, b^2 is the same as a^2 + 20^2, so you can exchange them freely.
how did you get them squared???
You get\[29^2 + (a^2 + 20^2) = (21+a)^2\]
This is now an equation with one variable, which you should be able to solve pretty easily.
Oh, they're squared from the pythagorean theorem. You know, a^2+b^2=c^2?
oh okay!! I'm gonna try to solve that one and send you what I got as an answer/
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Yeah I can't even solve that....
You've never solved a quadratic equation?
not that i remember
i thought i was supposed to put a/21=b/29?
That was the second solution. But then what do you do? You need a second equation, which you can only get from the Pythagorean Theorem.
then cross multiply?
this is so confusing.
You need to talk to your teacher. I can't teach you quadratics over OpenStudy...it's too complicated.
You're missing a lot of basic skills.
okay. thank you for the help.
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