0.4y^2 + 0.6y^2-0.2y^2

Question

anonymous · Answer

Do you need help simplifying?

anonymous · Answer

yes plz

anonymous · Answer

Okay~ $$0.4y ^{2} + 0.6y ^{2} - 0.2y ^{2}$$ 
Apply the exponent rules. When you add/ multiply exponents with the same  base, leave the base the same (if not, multiply them) and add the exponents only if the variable is the same. If subtracting, subtract exponents. Example: 2x^2 + 3x^3 = 6x^5

anonymous · Answer

So multiply 0.4 x 0.6 x -0.2  
and add 2 + 2 + 2 (exponents)

anonymous · Answer

So the variable should end up to be y^6 
$$y ^{2} + y ^{2} + y ^{2} = y ^{6} $$

anonymous · Answer

thanx

anonymous · Answer

you're welcome :) 
I have to change my answer, you leave the exponents alone when adding or subtracting. You only add the base.

anonymous · Answer

ohh now i get it thanx u saved me

anonymous · Answer

Anytime. You can ask me anytime for help with algebra, polynomials, pythogorean theorem, scale, angles, similarities, linear relations, exponents et cetera. :)