Question

4/(x-2)+4/3=8/3

Answer 1

\[\frac{ 4 }{ x+2 } +\frac{ 4 }{ 3 } = \frac{ 8 }{ 3 }\]

Answer 2

*** \[\frac{4}{x-2}+\frac{4}{3}=\frac{8}{3}\]

Answer 3

Makes the denominators equal everywhere so:

\[(\frac{ 4 }{ x-2 } x \frac{ 3 }{ 3 })+ (\frac{ 4 }{ 3 }x \frac{ x-2 }{ x-2 })= (\frac{ 8 }{ 3 }x \frac{ x-2 }{ x-2 })\]

Answer 4

Yeah x-2, sorry.

Answer 5

is the answer 5

Answer 6

12 + 4x-8 = 8x-16

20 = 4x
x = 5

Answer 7

Yes

Answer 8

4/(x-2)=8/3-4/3
4/(x-2)=4/3
1/(x-2)=4/3
x-2=3/4
x=(3/4)+2
x=11/2

Answer 9

thanq dear

Answer 10

@nitz How'd you get from the second, to the third step?

Answer 11

4/(x-2)+4/3=8/3
\[\frac{4}{x-2}+\frac{4}{3}=\frac{8}{3}\]
\[\frac{4}{x-2}=\frac{8}{3}-\frac{4}{3}\]
\[\frac{4}{x-2}=\frac{4}{3}\]
\[x-2=3,x=5\]

Answer 12

4 is not 4
lol

Answer 13

sorry.....its
1/(x-2)=1/3
x-2=3
x=5

Answer 14

meant 4 is not 1
lol

Answer 15

thanq all