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Mathematics 8 Online
OpenStudy (amtran_bus):

I really need help.

OpenStudy (amtran_bus):

From a hilltop to the west of Willy, Oompa Loompas launch gum balls out of slingshots toward his canoe. These gum balls travel in a linear path, dropping 3.2 meters as they travel eastward 15.3 meters to strike the canoe. 1. What's the distance from the Oompa Loompas to the canoe? 2. What is the angle, measured from the horizon, that the Oompa Loompas are firing from? 3. Is it possible for a sling sot propelled gumball to travel in a linear path? If not, what is the flaw in this logic?

OpenStudy (amtran_bus):

If I have it drawn right, part a is the pyth. theorem.

OpenStudy (amtran_bus):

|dw:1360440654830:dw|

OpenStudy (amtran_bus):

Maybe law of sines for part two?

OpenStudy (klimenkov):

I am not very good in English, but if your pic is correct, you found the distance right.

OpenStudy (amtran_bus):

Thanks so much! I think I drew it right. @Jonask what do you think?

OpenStudy (anonymous):

yes for 2|dw:1360448299629:dw|

OpenStudy (amtran_bus):

Awesome. Could I take the arctan?

OpenStudy (amtran_bus):

Whoops, no. I ment the law of sines.

OpenStudy (klimenkov):

\(\theta\) on the @Jonask 's pic is not measured from the horizon.

OpenStudy (anonymous):

No matter which angle you search, the law of sines is a ratio, it is mainly used to to find specific sides, but in such a right-angled triangle, as it seems (only judging by the picture - I haven't fully read the problem) you wouldn't want to use that law, more likely the regular trigonometric functions and solve for the angle.

OpenStudy (amtran_bus):

Where is the horizon?

OpenStudy (amtran_bus):

I wonder if it is a right triangle, from part 4.

OpenStudy (klimenkov):

|dw:1360441416725:dw|

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